Question

Q6. If 4m +8, 2m² +3m +6,3m²+ 4m+4 are three Consecutive terms of A.P. Find m. (Answer: m=0, 2]​

Answer 1

Answer:

since the given terms are in AP

second term - first term = third term - second term

(2m^2 + 3m + 6) - (4m + 8). = (3m^2 + 4m + 4) - (2m^2 + 3m + 6)

= 2m^2 + 3m + 6 - 4m - 8 = 3m^2 + 4m + 4 - 2m^2 - 3m - 6

= 2m^2 - m - 2 = m^2 + m - 2

2m^2 - m^2 - m - m - 2 + 2 = 0

m^2 - 2m = 0

m(m - 2) = 0

m = 0, 2