Question

Q6. If cos =8/7
- find the other five trigonometric ratios.
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Answer 1

first of all, cosine can't be greater than 1

here cos = 8/7 > 1 is impossible.

I think your question is ---> cosec = 8/7

given, cosec$\theta$ = 8/7

we know, cosec$\theta$ = hypotenuse/perpendicular

after comparing we get,

hypotenuse = 8 and perpendicular = 7

from Pythagoras theorem,

base² = hypotenuse ² - perpendicular ²

= 8² - 7² = 64 - 49 = 15

so, base = √15

now, sin$\theta$ = perpendicular/hypotenuse = 7/8

cos$\theta$ = base/hypotenuse

= √15/8

sec$\theta$ = hypotenuse/base

= 8/√15

tan$\theta$ = perpendicular/base

= 7/√15

cot$\theta$ = base/perpendicular

= √15/7