Question

Q6 if the angles of a triangle ABC are in the ratio 2:3:4 find the measure of the angles A, B and C

Answer 1

Given

the angles of a triangle ABC are in the ratio 2:3:4

To find

Each and every angle of the triangle

Explanation:

$\sf in\: \bigtriangleup ABC,$

Angles are In the ratio=2:3:4

let the angles be 2x,3x,4x

$\boxed{\bf sum \:of\: all\: angles \:in \:a \:\bigtriangleup le =180\degree}$

So,

$=> 2x+3x+4x=180\degree$

$=>9x=180\degree$

$=>x=20\degree$

Now

Angle 1:

$2x = > 2 \times 20 = 40 \degree$

Angle 2:

$3x = > 3 \times 20 = 60 \degree$

Angle 3:

$4x = > 4 \times 20 = 80 \degree$

Therefore

$\boxed{\sf angles \: of \: \bigtriangleup ABC=40\degree,60\degree,80\degree}$

Answer 2

AnswEr :

⠀

Angles of $\triangle$ ABC is 40°, 60° and 80° respectively.

⠀

Explanation :

⠀

• Angles of $\triangle$ ABC are in Ratio = 2:3:4

Let the Angles be 2x , 3x and 4x.

$\boxed {\bf{Sum \: of \: Angles \: of \: Triangle = 180°}}$

➟ ∠A + ∠B + ∠C = 180°

➟ 2x + 3x + 4x = 180°

➟ 9x = 180°

➟ $\bf{x = \cancel\dfrac{180}{9} }$

➟ x = 20

⠀

_________________________________

▣ ∠A = 2x = (2 × 20) = 40°

▣ ∠B = 3x = (3 × 20) = 60°

▣ ∠C = 4x = (4 × 20) = 80°

⠀

$\large\therefore$ Angles of $\triangle$ ABC is 40°, 60° and 80° respectively.