Q6. Ifa, Band y are zeros of the polynomial 6x² + 3x? -5x +1, then find the value
of a +B+1+y".
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Answer:
the sum of roots of a cubic equation is given by
-b/a
here b= 3, a= 6
(though in question, the first term is 6x^2, I am assuming it to be 6x^3 as a quadratic equation cannot have three roots)
now
a + b + 1 + y
= a + b + y + 1
= sum of roots + 1
= [-b/a] + 1
= (-3/6) + 1
= -1/2 + 1
= 1/2
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