Question

Q6. In the
fig. Ab = cd and angle abc = angle bcd. prove ac = bd and be = ce​

Answer 1

Answer:

According to the figure ,

AD=BC and angle ADC =angle BCD

We have to prove AC=BD

Lets see ΔADC and ΔBCD

AD=BC [given]

angle ADC =angle BCD [Given]

CD=CD

from S-A-S

ΔADC congruence ΔBCD

and we know,that triangles are congruence means both are identical in shape and size

So,AC=BD[Hence proved]