Question

Q6
Rohan walks 5 km in the East. Then, he
turns perpendicularly left and walks 12
km. Now, at least how many kilometres
will he have to walk to come back to the
starting point ?
7 km
) 17 km
08.5 km
13 km​

Answer 1

Answer:

0.85

Step-by-step explanation:

this answer is correct

Answer 2

Answer:

He has to walk at least 13km to reach to the starting point.

Step-by-step explanation:

Given,

Rohan walks 5km in the East. Then, he turns perpendicularly left and walks 12km

To find,

The least distance he has to walk to come back to the starting point.

Recall the concept:

Pythagoras Theorem:

The square of the hypotenuse is equal to the sum of squares of the other two sides.

In the figure, AB is the distance traveled to the east and BC is the distance traveled to the left.

AB ⊥BC

Then ΔABC is a right-angled triangle.

The minimum distance to be traveled to reach the starting point is the hypotenuse of the right-angled triangle ABC

That is we need to find the length of AC

Then, by Pythagoras theorem,

AC² =AB² + BC²

AC² = 12² + 5² = 144+25 = 169 = 13²

AC = 13km

∴ He has to walk at least 13km to reach to the starting point.

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