Question

Q6 The hypotenuse of a right triangle with its legs of length 3x and 4x is​

Answer 1

Given legs are 3x and 4x

By Pythagoras Theorem,

hypotenuse² = (3x)² + (4x)²

hypotenuse² =  9x² + 16x²

hypotenuse²  = 25x²

hypotenuse  = √25x²

hypotenuse = 5x

Therefore the hypotenuse is 5x.

Answer 2

$\sf \bf \huge{Answer}$

Perpendicular sides of the right angle triangle are 3x and 4x .
$\sf \longrightarrow {h}^{2} = {(4x)}^{2} + {(3x)}^{2}$
$\sf \longrightarrow \: {h}^{2} = 16 {x}^{2} + 9 {x}^{2}$
$\sf \longrightarrow {h}^{2} = 25 {x}^{2}$
$\sf \longrightarrow h = \sqrt{25 {x}^{2} }$
$\sf \longrightarrow \bf h =5x$
$\underline{\rm \bf \: Hypotenuse \: = \: 5x}$