Science, asked by faisalparray170, 10 months ago

Q6: The speed of a car weighing 1500 kgs increases from 36 km/hr to 72 km/hr
uniformly. What will be the change in the momentum of car:
a) 15000 kg km/hr
b) 15000 kg m/s
c) 54000 kg m/s
d) 54000 g m/s​

Answers

Answered by Saby123
29

Correct Question -

The speed of a car weighing 1500 kg increases from 36 km/hr to 72 km/hr uniformly.

What will be the change in the momentum of car ?

a) 15000 kg km/hr

b) 15000 kg m/s

c) 54000 kg m/s

d) 54000 g m/s

the above Question , the following information is given -

The weight of the car is 1500 kg .

The initial Velocity of the car is 36 kmph

The final Velocity of the car is 72 kmph .

So ,

Change in velocity of car -

∆V

=> 72 - 46

=> 36 kmph

Now

The mass of the car is 1500 kg

Change In Momentum

=> mv² - mv¹

=> m ( v² - v ¹ )

=> m ∆ v

=> 1500 × 36 kg kmph

=> 5400 kg kmph

Now, none of the options matches let change the units.

So ,

Initial Velocity

=> 36 kmph

=> 36 × ( 5 / 18 ) m /s.

=> 10 m / s.

Final velocity

=> 72 kmph

=> 72 × ( 5 / 18 ) m / s

=> 20 m /s.

∆ V

=> 10 m / s

Change in Momentum -

=> m ∆ v

=> 1500 × 10 kg m / s

=> 15000 kg m / s.

Hence , option B is the correct answer.

________

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
42

\huge\sf\pink{Answer}

☞ Your answer is option b

\rule{110}1

\huge\sf\blue{Given}

✭ Weight of the car = 1500 kg

✭ Speed changes from 36 km/h to 72 km/h

\rule{110}1

\huge\sf\gray{To \:Find}

☆ Change in the momentum of the car?

\rule{110}1

\huge\sf\purple{Steps}

Initial velocity = 36 km/h = 36 × \sf\dfrac{5}{8} = 10m/s

Final velocity = 72 km/h = 72 × \sf\dfrac{5}{8} = 20m/s

So the change in momentum is given by,

\underline{\boxed{\green{\sf P = mv - mu}}}

Substituting the given values,

➝ 1500 × 20 - 1500 × 10

➝ 30000 - 15000

\sf\orange{P = 15000\: km/s}

\rule{170}3

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