Question

Q6a) Calculate the number of
Chloride ions in 222 g of
Calcium Chloride (CaCl2).​

Answer 1

Given :

• 222g of Calcium chloride (CaCl2)

To find :

Number of Chloride ions

Formula used :

• Number of mole = given mass ÷ molar mass
• Number of molecules = Number of mole × Avogadro's number
• Number of atom/ion = Total Number of molecules × (Number of ion in one molecules)

Additional points :

◕ Molar mass of Calcium chloride = 111 g/mol

◕

$\sf \: CaCl_2\: ➝\: Ca^{+2}\: + \:2Cl^-$

Solution :

✪ Number of moles of CaCl2 = 222÷111

➠ Number of moles of CaCl2 = 2mol

✪ Number of molecules of CaCl2 = 2 × Avogadro's number

✪ 1 molecule of CaCl2 contain 2 ion of Cl

➠ Number of Chloride ion = 2 × (2 × 6.02 ×10²³)

➠ Number of Chloride ions = 24.08 × 10²³

➠ Number of Chloride ions = 2.408 × 10²⁴

ANSWER :

Number of Chloride ions = 2.408 × 10²⁴