Question

Q6The solution of the equation – 4 = 2 (p – 2) is(a) 0(b) 1(c) 2(d) 4 *​

Answer 1

$\large{\text{\red{A}}}{\text{\orange{N}}{\text{\green{S}}{\text{\purple{W}}{\text{\blue{E}}{\text{\pink{R}}{\text{\gray{:-}}}}}}}}$

$\bf{\large{ - 4 = 2(p - 2)}}$

$\bf{{ = > - 4}} = {\blue{2p - 4}}$

$\bf{ = > - 4 +{\blue{ 4} = {{2p - 4 + {\blue{4}}}}}}$

$\bf{ = > 0 = 2p}$

$\bf{ = > \frac{0}{\blue{2}}} = \frac{2p}{\blue{2}}$

$\bf{ = > p = 0}$

Hence, the solution of the equation – 4 = 2 (p – 2) is 0.

Answer 2

Step-by-step explanation:

By applying the rules of bodmas we would solve the brackets first

-4 = 2p - 4

Taking -4 to the right hand side it's sign would change

-4 + 4 = 2p

0 = 2p

0/2 = p

• p = 0

hope it helps you!!