Question

Q7 A baseball is thrown with an initial velocity of 100 m/s at an angle of 300 above the horizontal. How far from the throwing point will the baseball attain its original level?

Answer 1

Answer:

Horizontal range is given by,

R = u² sin2x/g

Given, u = 100 m/s, angle x = 30°, g = 10 m/s²

Putting values, we get

R = 100² × sin60°/ 10

R =(100 × 100 × √3)/20 = 17320/20

R = 866 m