Question

Q7 and Q8.
Please. I need help. And it's really urgent.

Answer 1

solution 7
If ABCD is a rhombus,
area of rhombus=216 cm²
diagonal(BD)=24 cm
diagonal(AC)=?
AB=BC=CD=DA

Area of rhombus =
$\frac{1}{2} diagonal(1) \times diagonal(2)$
AC=(216×2)÷24
AC=18 cm

In ∆AOB
BO=1/2.BD=12
AO=1/2.AC=9
AB²=AO²+BO²
AB =√[12²+9²]
AB=15 cm
AB=BC=CD=DA=15cm