Question

Q7: How much work done to displace horizontally a body 400 cm by a force of 200N whose
angle with the horizontal is 30°?​

Answer 1

Answer:

The work done is 692.8 J.

Explanation:

We have given that,

• Displacement ( s ) = 400 cm = 4 m
• Force ( F ) = 200 N
• Angle with horizontal ( θ ) = 30°

We have to find the work done.

Now, we know that,

$\displaystyle{\pink{\sf\:Work\:done\:=\:Force\:\times\:Displacement\:\times\:\cos\:\theta}}$

$\displaystyle{\implies\sf\:W\:=\:F\:\times\:s\:\times\:\cos\:30^{\circ}}$

$\displaystyle{\implies\sf\:W\:=\:200\:N\:\times\:\cancel{4}\:m\:\times\:\dfrac{\sqrt{3}}{\cancel{2}}}$

$\displaystyle{\implies\sf\:W\:=\:200\:\times\:2\:\times\:\sqrt{3}\:N\:.\:m}$

$\displaystyle{\implies\sf\:W\:=\:400\:\times\:\sqrt{3}\:N\:.\:m}$

$\displaystyle{\implies\sf\:W\:=\:400\:\times\:1.732\:joules}$

$\displaystyle{\implies\sf\:W\:=\:692.8\:joules}$

$\displaystyle{\implies\underline{\boxed{\red{\sf\:Work\:done\:=\:692.8\:J\:}}}}$

∴ The work done is 692.8 J.

Answer 2

(｡◕‿◕｡)

Answer

• Given,

➜ Displacement ($) = 400 cm

= 4m

➜ Force (F) = 200 N

➜ Angle with horizontal (cos) = 30°

• Find, Work done
• We know,

Work done(W)= F × $ × cos

☞ W = 200 N × 4m × √3 / 2

☞ W = 200 N × 2m × √3

☞ W = 200 × 2 × √3 N.m

☞ W = 400 × √3 N.m

☞ W = 400 × 1.732 joules

☞ W = 692.8 joules

WoRk DoNe = 692.8 J