Question

Q7. The displacement x in time t is given by the relation; x=(t+a)/b + t2 b /c where a, b and c are constants. The dimensions of a, b and c are: (a) T, L T – 1 and L– 2 T3 (b) T, L–1T and L2T–3 (c) T, L– 1 T and L– 2 T3 (d) T, L–1T–1 and L–2T3

Answer 1

Answer:

Ans c

Explanation:

$x = \frac{(t + a)}{b} + \frac{ {t}^{2} b}{c} \\ acc \: to \: rule \:only \: term \: has \: same \: dimentions \: are \: added \: or \: subs \\ so \: a = t \\ b = {l}^{ - 1} t \\ c = {l}^{ - 2} {t}^{ 3}$