Question

show that 5is 0of 2xcube-7xsquare-16x+5​

Answer 1

Answer:

let p(x) = 2x³-7x²-16x+5

now put , x= 5

=> p(5) = 2(5)³-7(5)²-16(5)+5

=> p(5) = 2×125 - 7×25 - 16×5 + 5

=> p(5) = 250-175-80+5

=> p(5) = 255-255

=> p(5) = 0

THEREFORE ,

p(5) = 5

So , 5 is the zero of polynomial p(x) = 2x³-7x²-16x+5

HOPE, IT IS HELPFUL TO YOU!!

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