Question

Q8. ਜੇਕਰ ਤ੍ਰਿਭੁਜਾਂ ABC ਅਤੇ DEF ਸਮਰੂਪ ਹੋਣ ਅਤੇ CA = 47°ਅਤੇ E = 83 ਹੋਣ
ਤਾਂ ਪਤਾ ਕਰੋ ।
if triangle ABC and triangle DEF are similar triangles such that ZA= 47°
and LE = 83°, then find the value of 0.
यदि त्रिभुज ABC और DEF समरूप त्रिभुजें हैं जिस में कि CA = 47° और
-E = 83°, तो Zc का मूल्य पता लगाएं
a) 50

b) 60

c) 55

d) 80​

Answer 1

Step-by-step explanation:

It has given that, sides of a right angled triangle are ; 6 cm, 8cm and 10 cm.

we have to find the length of perpendicular drawn to the hypotenuse from the opposite vertex.

solution : let length of perpendicular drawn to the hypotenuse is x cm.

let right angled triangle is ∆ABC where B is right angle. and we draw a perpendicular B to AC which touches AC at T.

here, ∠BAT = ∠BAC

and ∠BTA = ∠ABC

so, ∆ATB ~ ∆ABC

then, AB/AC = BT/BC

⇒6cm/10cm = BT/8 cm

⇒BT = 48/10 = 4.8 cm

Therefore the length of perpendicular drawn to hypotenuse is 4.8 cm

A part of the line intersected between the axes is bisected at the point (2, -5).

we have to find the length of the perpendicular drawn from origin to the line.

solution : let line intersects x - axis at (α, 0) and y - axis at (0, β).

(2, -5) is the midpoint of (α, 0) and (β, 0)

using midpoint section formula,

2 = (α + 0)/2 ⇒α = 4

-5 = (0 + β)/2 ⇒β = -10

Therefore the equation of line is x/α + y/β = 1

⇒x/4 + y/-10 = 1

⇒5x - 2y = 20

now let length of perpendicular drawn origin to line is h

area of triangle = 1/2 × base × height

⇒1/2 × 4 × 10 = 1/2 × √(4² + 10²) × h

⇒40/√116 = h

⇒h = 10/√29

Therefore the length of perpendicular drawn from origin to the line is 10/√29 unit