Question

root of x²+3x+8 + (x+4)i = y(2+i). x,y=?

answer this asap pls (with proper explanation)​

Answer 1

$Answer ⤵️⤵️✅✅$

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Step by step solution :

STEP

1

:

Trying to factor by splitting the middle term

1.1 Factoring x2-3x-8

The first term is, x2 its coefficient is 1 .

The middle term is, -3x its coefficient is -3 .

The last term, "the constant", is -8

Step-1 : Multiply the coefficient of the first term by the constant 1 • -8 = -8

Step-2 : Find two factors of -8 whose sum equals the coefficient of the middle term, which is -3 .

-8 + 1 = -7

-4 + 2 = -2

-2 + 4 = 2

-1 + 8 = 7

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step

1

:

x2 - 3x - 8 = 0

STEP

2

:

Parabola, Finding the Vertex:

2.1 Find the Vertex of y = x2-3x-8

Plugging into the parabola formula 1.5000 for x we can calculate the y -coordinate :

y = 1.0 * 1.50 * 1.50 - 3.0 * 1.50 - 8.0

or y = -10.250

Parabola, Graphing Vertex and X-Intercepts :

Root plot for : y = x2-3x-8

Axis of Symmetry (dashed) {x}={ 1.50}

Vertex at {x,y} = { 1.50,-10.25}

x -Intercepts (Roots) :

Root 1 at {x,y} = {-1.70, 0.00}

Root 2 at {x,y} = { 4.70, 0.00}

Answer 2

Answer:

$\sqrt{ {x }^{2} + 3x \times 8 + (x + 4i } = y(2 + i).xy =$