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Q8. For the differential equation x2 + x - (secx) y = 0, (a) x=0 is a irregular singular (b)x=0 is a regular singular point. (c) x=0, (d)x=1is a regular singular point.​

Answers

Answered by Anonymous
3

Answer:

Step-by-step explanation:

Hence, if we omit the constant multiplier a0

, one solution of Eq. (8) is

y1

(x) = x

1 +

n=1

(−1)

n

x

n

[3 · 5 · 7 ···(2n + 1)]n!

, x > 0. (19)

To determine the radius of convergence of the series in Eq. (19) we use the ratio test:

lim

n→∞

an+1

x

n+1

an

x

n

= lim

n→∞

|x|

(2n + 3)(n + 1)

= 0

for all x. Thus the series converges for all x.

Corresponding to the second root r = r

2 =

1

2

, we proceed similarly. From Eq. (17)

we have

an = −

an−1

2n(n −

1

2

)

= −

an−1

n(2n − 1)

, n ≥ 1.

Hence

a1 = −

a0

1 · 1

,

a2 = −

a1

2 · 3

=

a0

(1 · 2)(1 · 3)

,

a3 = −

a2

3 · 5

= −

a0

(1 · 2 · 3)(1 · 3 · 5)

,

and in general

an =

(−1)

n

n![1 · 3 · 5 ···(2n − 1)]

a0

, n ≥ 1. (20)

Again omitting the constant multiplier a0

, we obtain the second solution

y2

(x) = x

1/2

1 +

n=1

(−1)

n

x

n

n![1 · 3 · 5 ···(2n − 1)]

, x > 0. (21)

As before, we can show that the series in Eq. (21) converges for all x. Since the leading

terms in the series solutions y1

and y2

are x and x

1/2

, respectively, it follows that the

solutions are linearly independent. Hence the general solution of Eq. (8) is

y = c1

y1

(x) + c2

y2

(x), x > 0.

The preceding example illustrates that if x = 0 is a regular singul

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