Question

Q8. Options:

(a) 5 litre
(b) 10 litre
(c) 4 litre
(d) 5 litre​

Answer 1

ANSWER:

$\text{We know that, the Ideal Gas Equation says,}\\\\\text{ :\implies PV = nRT}\\\\\text{Where,}\\\\\text{ :\hookrightarrow P = Pressure of the gas,}\\\\\text{ :\hookrightarrow V = Volume of the gas,}\\\\\text{ :\hookrightarrow n = Number of moles of the gas,}\\\\\text{ :\hookrightarrow R = Ideal Gas constant, and}\\\\\text{ :\hookrightarrow T = Temperature of the gas.}\\\\\text{Here,} \:P=0.4atm, \:V=20L,\: n=n_{CO_2}, \:\&\: T=400K.\\\\\text{So,}\\\\:\implies (0.4 atm)\times(20L)=n_{CO_2}\times R\times 400K\\\\:\implies n_{CO_2}\times R=\dfrac{0.4\times20\!\!\!\!/}{400\!\!\!\!\!\!/_{\:\:20}}=\dfrac{4\!\!\!/^{\:1}}{200\!\!\!\!\!/_{\:\:50}}=\dfrac{1}{50}\\\\:\implies n_{CO_2}\times R=0.02\\\\:\implies n_{CO_2}=\dfrac{0.02}{R}- - - -(1)$

$\text{After attaining Equilibrium, the reaction will be:}\\\\:\implies SrCO_3(s)\rightleftharpoons SrO(s)+CO_2(g)\\\\\text{As, the only gas present in the reaction is CO _2 }\\\\\text{All the pressure will be because of it. So,}\\\\:\implies K_p=P_{CO_2}=1.6atm.\\\\\text{Again, using Ideal Gas equation,}\\\\:\implies P_{max}V_{max}=nRT \\\\:\implies(1.6atm)\times(V_{max})=n_{CO_2}\times R\times (400K)\\\\\text{From (1),}\\\\:\implies(1.6atm)\times(V_{max})=\dfrac{0.02}{R\!\!\!/}\times R\!\!\!/\:\times400K\\\\:\implies V_{max}=\dfrac{0.02\times400}{1.6}=\dfrac{8}{1.6}\\\\:\implies V_{max}=\dfrac{80\!\!\!\!/^{\:5}}{16\!\!\!\!/_{\:1}}\\\\\bf{:\implies V_{max}=5L}\\\\\text{\bf{Hence, the max volume of CO _2 at its max pressure is 5litres}}$

Answer 2

Answer:

5 litre is the correct answer

Explanation:

We know that, the Ideal Gas Equation says,

:⟹ PV = nRT

Where,

:↪ P = Pressure of the gas,

:↪ V = Volume of the gas,

:↪ n = Number of moles of the gas,

:↪ R = Ideal Gas constant, and

:↪ T = Temperature of the gas.

Correct option is A] 5 litre