Math, asked by Anonymous, 11 months ago

Q8.
Solution of the equation 3(y - 1) - 2 (y - 2) = 0 is
(a) 1
(b) -1
(c) 2​

Answers

Answered by sarikadimri2018
1

Answer:

(3×y-3×1)-(2×y+2×2)=0

3y-3-2y+4=0

=y+1=0

Answered by janu9833
1

Answer:

-1

Step-by-step explanation:

3(y - 1) - 2(y - 2) = 0 \\ 3y - 3 - 2y   + 4 = 0 \\ 3y - 2y + 4 - 3 = 0 \\ y + 1 = 0 \\ y =  - 1

Similar questions