Question

Q8. The sides of a triangle are
8cm, 11cm, and 13cm. What is
its area?
(A) 8√30 cm sq
(B) 4√10 cm sq
(C) 3√100 cm sq.
(D) 6√200 cm sq.​

Answer 1

Given:

•Sides of triangles 8 cm, 11 cm, 13 cm

To Find:

•Area of Triangle

Step-by-step Solution:

•a = 8 cm

•b = 11 cm

•c = 13 cm

Perimeter = a+b+c

$= 8 + 11 + 13 \\ = 32 \: cm$

Semi-perimeter = a+b+c/2

$= \frac{(8 + 11 + 13)}{2} = \frac{32}{2} \\ = 16 \: cm$

Area of Triangle= $\sqrt{s(s - a)(s - b)(s - c)}$

$= \sqrt{16(16 - 8)(16 - 11)(16 - 13)} \\ = \sqrt{16 \times 8 \times 5 \times 3} \\ = \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 3} \\ = 2 \times 2 \times 2 \sqrt{2 \times 5 \times 3} \\ = \sqrt[8]{30}$

Answer 2

Answer:

option a is correct.....