Math, asked by avanshika63, 8 months ago

Q8. The sides of a triangle are
8cm, 11cm, and 13cm. What is
its area?
(A) 8√30 cm sq
(B) 4√10 cm sq
(C) 3√100 cm sq.
(D) 6√200 cm sq.​

Answers

Answered by Anonymous
4

Given:

Sides of triangles 8 cm, 11 cm, 13 cm

To Find:

Area of Triangle

Step-by-step Solution:

a = 8 cm

b = 11 cm

c = 13 cm

Perimeter = a+b+c

 = 8 + 11 + 13 \\  = 32 \: cm

Semi-perimeter = a+b+c/2

 =  \frac{(8 + 11 + 13)}{2}  = \frac{32}{2}  \\  = 16 \: cm

Area of Triangle=  \sqrt{s(s - a)(s - b)(s - c)}

  =  \sqrt{16(16 - 8)(16 - 11)(16 - 13)}  \\  =  \sqrt{16 \times 8 \times 5 \times 3}  \\  =  \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 5 \times 3}  \\  = 2 \times 2 \times 2 \sqrt{2 \times 5 \times 3}  \\   = \sqrt[8]{30}

Answered by emailquacky4
0

Answer:

option a is correct.....

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