Question

Q8. The sum of two numbers is 20. If twice the first number x is 13 more than second number y, frame the equations for the given statements. ​


Solve please don't spam ❎ spammer stay away

Answer 1

Explanation:

Given:-

▪ Sum of two numbers is 20.

▪ Twice the first number x is 13 more than second number y.

To Find :-

▪ Equations for the given condition

Solution :-

Let the numbers be x and y respectively.

According to the question,

Case 1 :-

☞ The Sum of the two numbers is 20

Numbers we assumed are x and y.

∴ x + y = 20 ...(1)

Case 2 :-

☞ Twice the number x is 13 more than y.

Numbers we assumed are x and y.

⇒ 2x = y + 13

⇒ 2x - y = 13 ...(2)

Hence, The equations for this given condition are,

x + y = 20

2x - y = 13

Let us find the required numbers,

Adding (1) and (2),

⇒ x + y + 2x - y = 20 + 13

⇒ 3x = 33

⇒ x = 11

Substituting x = 11 in (1)

⇒ 11 + y = 20

⇒ y = 20 - 11

⇒ y = 9

Hence, The numbers are 11 and 9.

Answer 2

Length of rectangular park is 23 cm and breadth is 21 cm. Find the are of rectangular park.

Answer:

Area = Length × breadth

= 23 cm × 21 cm

= 483 cm²