Q9. 400 J of heat is produced in 4s in a 4 Ω resistor. Find potential difference across the resistor.
Answers
Answered by
18
Given:
Heat = 400J
Time t = 4s
Resistance = 4Ω
Formula:
Heat produced H = i²Rt
H=(V/R)²Rt
H=V²t/R
V² = HR/t
V = √(400×4/4)
V = 20 V
Therefore, The potential difference across the resistor is 20V
Heat = 400J
Time t = 4s
Resistance = 4Ω
Formula:
Heat produced H = i²Rt
H=(V/R)²Rt
H=V²t/R
V² = HR/t
V = √(400×4/4)
V = 20 V
Therefore, The potential difference across the resistor is 20V
Answered by
8
HELLO DEAR ,
____________________
Given,
☆Heat produced, H=W=100 J
☆Resistance, R=4 ohm
●Using relation,H = I^2Rt
=(V/R)2×R×t
=V^2/R×t
●Putting the values,
100=V^2/4×1
_______________\\
=> Or V= 20 volt. --------- ( Ans.)
=================//
■■ Potential difference across the resistance is 20 volt. ■■
______________________
Hope it helps u !!!!
Have a wonderful day ahead :))
Cheers !!✌✌
# Nikky
____________________
Given,
☆Heat produced, H=W=100 J
☆Resistance, R=4 ohm
●Using relation,H = I^2Rt
=(V/R)2×R×t
=V^2/R×t
●Putting the values,
100=V^2/4×1
_______________\\
=> Or V= 20 volt. --------- ( Ans.)
=================//
■■ Potential difference across the resistance is 20 volt. ■■
______________________
Hope it helps u !!!!
Have a wonderful day ahead :))
Cheers !!✌✌
# Nikky
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