Q9-If a+b+c=9 and ab + bc+ ca = 26, find a2+b2+c2 .
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(a+b+c)^2 = 81
a^2 + b^2 + c^2 + 2(ab+ bc+ ca) = 81
a^2 + b^2 + c^2= 81 - 52 = 29
a^2 + b^2 + c^2 + 2(ab+ bc+ ca) = 81
a^2 + b^2 + c^2= 81 - 52 = 29
Answered by
0
Answer:
29
Step-by-step explanation:
(a+b+c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(9)2= a2 +b2 +c2 + 2 (ab+bc+ca)
81=a2+b2+c2+2(26)
81= a2+b2+c2+52
81-52 = a2+b2+c2
29= a2+b2+c2
hope it helps
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