Question

Q9
Please answer quickly

Answer 1

Let O be the centre of the circle.

In this ∆ ABC, BP and BQ work as a tangents

then

BP=BQ=2 cm,

also

angle B=90°,

angle P = angle Q = 90°,

(angle made by tangent and radius of the Circle),

hence

we can say they OPBQ is a square,

then

OP=BP=radius=2 cm,

therefore

diameter=2×r=2×2=4cm