Question

Q9) What is the sum of the first 16 terms of the AP: 10, 6, 2, ----?​

Answer 1

Answer:

sum of n terms of AP=n/2(2a+(n-1)×d)

sum of 16 terms of AP=8((20+15×-4)=-320

Answer 2

Answer:

Lets see -

Step-by-step explanation:

N = 16

A= 10

and D = -4

Sn=

$\frac{16}{2} ( 2 \times 10 + 15 \times - 4)$

$\frac{16}{2} (20 - 60)$

8 x -40

= -320

Hope it helps.