Math, asked by kshma71, 1 year ago

qa wire is in the shape of a square of side 12cm. it is again bent into a rectangle of length 15 cm find its breadth which encloses more area and how much

Answers

Answered by dronmishra
28
the side of squre=12cm
the perimeter of squre=4×12
=48cm
the area of squre =12×12
=144cm squre
the perimeter of squre=the perimeter of rectangle
because they are made by same wire
then
the perimeter of rectangle=48cm
length of rectangle =15cm
formuma=2(l+b)
2(15+b)=48cm
30+2b=48
2b=48_30
b=18/2
b=9cm
the area of rectangle=l×b
=15×9
=135cm squre
144>135
mean
area of squre>area of rectangle
144cm squre_135cm squre=9cm squre
the area of squre is 9cm squre bigger then the area of rectrangle
Answered by lAnniel
14

\huge\rm\underline\purple{Question :-}

A wire is in the shape of a square of side 12 cm. It is again bent into a rectangle of length 15 cm. Find it breadth which encloses more area and how much.

\huge\rm\underline\purple{Answer :-}

\sf Given\begin{cases} &\sf{Side\;of\;the\; square, \; a=\be{12\:cm}}\\&\sf{Length\;of\;the\;rectangle,\;l =\bf{15\;cm}}\end{cases}\\ \\

✏ Here, the square is bent into a rectangle. So, the length of the wire will be same.

\red{\underline\bold{To\: find,}}

  • Breadth of the rectangle = ❓

\green{\underline\bold{For\: the\:square,}}

  • Side of the square = a = 12 cm

⇒Perimeter = 4a

= 4 × 12

= 48 cm

\green{\underline\bold{For\: the\:rectangle,}}

  • Length of the rectangle,l = 15 cm
  • Breadth of the rectangle,b = ?

⇒Perimeter = 2 × (l + b)

= 2 × (15 + b)

\pink{\underline\bold{Here,}}

\orange{\underline\bold{Perimeter\: of\:the\:square\: = \:Perimeter\: of\: the\: rectangle}}

⇒48 = 2 × (15 + b)

⇒(15 + b) = \frac{48}{2}

⇒b = 24 - 15

⇒b = 9 cm

\pink{\underline\bold{ ∴ \:Breadth\:of\:the\:rectangle=\:9\: cm}}

\green{\underline\bold{For\:finding\:the\:area,}}

\blue{\underline\bold{For\: the\:square,}}

Area = a × a

= 12 × 12

= 144 cm2

\blue{\underline\bold{For\: the\:rectangle,}}

Area = l × b

= 135 cm2

\purple{\underline\bold{So,\: area\:of\: the\: square \:is \:greater\: than \:area \:of \:a\: rectangle.}}

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