qa wire is in the shape of a square of side 12cm. it is again bent into a rectangle of length 15 cm find its breadth which encloses more area and how much
Answers
Answered by
28
the side of squre=12cm
the perimeter of squre=4×12
=48cm
the area of squre =12×12
=144cm squre
the perimeter of squre=the perimeter of rectangle
because they are made by same wire
then
the perimeter of rectangle=48cm
length of rectangle =15cm
formuma=2(l+b)
2(15+b)=48cm
30+2b=48
2b=48_30
b=18/2
b=9cm
the area of rectangle=l×b
=15×9
=135cm squre
144>135
mean
area of squre>area of rectangle
144cm squre_135cm squre=9cm squre
the area of squre is 9cm squre bigger then the area of rectrangle
the perimeter of squre=4×12
=48cm
the area of squre =12×12
=144cm squre
the perimeter of squre=the perimeter of rectangle
because they are made by same wire
then
the perimeter of rectangle=48cm
length of rectangle =15cm
formuma=2(l+b)
2(15+b)=48cm
30+2b=48
2b=48_30
b=18/2
b=9cm
the area of rectangle=l×b
=15×9
=135cm squre
144>135
mean
area of squre>area of rectangle
144cm squre_135cm squre=9cm squre
the area of squre is 9cm squre bigger then the area of rectrangle
Answered by
14
A wire is in the shape of a square of side 12 cm. It is again bent into a rectangle of length 15 cm. Find it breadth which encloses more area and how much.
✏ Here, the square is bent into a rectangle. So, the length of the wire will be same.
- Breadth of the rectangle = ❓
- Side of the square = a = 12 cm
⇒Perimeter = 4a
= 4 × 12
= 48 cm
- Length of the rectangle,l = 15 cm
- Breadth of the rectangle,b = ?
⇒Perimeter = 2 × (l + b)
= 2 × (15 + b)
⇒48 = 2 × (15 + b)
⇒(15 + b) =
⇒b = 24 - 15
⇒b = 9 cm
Area = a × a
= 12 × 12
= 144 cm2
Area = l × b
= 135 cm2
━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
Similar questions
Math,
7 months ago
English,
7 months ago
English,
1 year ago
History,
1 year ago
Psychology,
1 year ago