Question

Qid : 36 - if abcdef is a regular hexagon, then what is the value (in degrees) of adb?

Answer 1

Answer:

Each Interior angle of hexagon is of 120°

ΔCOD is a equilateral triangle

∠BCD = 120°

BC=CD

∠CBD =∠CDB  = $\frac{180-120}{2}$

∠BDC = 30 ∠ODC = 60

∠ADB = 60-30

∠ADB = 30°  answer

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