Question

Qn. 1.1.4. Determine k so that k + 2, 4k - 6 and 3k - 2 are the three
consecutive terms of an AP.
$nothing$
​

Answer 1

Step-by-step explanation:

Aloha !

Taking 2b=a+c

2(4k-6)=k+2+3k-2

8k-12=4k

8k-4k=12

4k=12

k=3

Thank you

@ Twilight Astro ✌️☺️❤️

Answer 2

Answer:

As we know that: 2b=a+c

2(4k-6)=k+2+3k-2

8k-12=4k

4k=12

k=3......

hope it will help you ✌️❤️