Qn 18 answer in paper pls
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Step-by-step explanation:
Given:α and β are zeroes of polynomial x^2-2x-15.
Therefore, sum of zeroes =α=-b/a
=2/1=2
And product of zeroes =c/a= -15*1=-15
So, zeroes are 2 or -15.
Now new zeroes = 2*2=4
And 2*-15=-30
We know that any quadratic equations is of the form x^2-(α+β)x+αβ
So, = x^2-(2)x+(-30)
= x^2-2x-30 is required quadratic equation. Hope it will help.... pls mark it as brainliest.
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