Qn. A and B are two electrical devices, Device A 230V 1000W Device B 230V 50W 1. If both the devices are working for the same time which among will produce more electrical Energy?
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Answer:
200 wats
Explanation:
Resistance of the 220V, 100W bulb is given by
R=
P
V
2
=
100
220
2
=484Ω
Thus, when connected in series, total resistance R
s
=484+484Ω
=968Ω
Power drawn in case of series combination,
P
s
=
R
s
V
2
=
968
220
2
=50W
When connected in parallel, total resistance R
p
=
2
484
Ω
=242Ω
Power drawn in case of series combination,
P
p
=
R
p
V
2
=
242
220
2
=200W
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