Qn: A heater coil connected to a supply of a 220V is dissipatting some power p. the coil is cut into half and two halves are connected in parallel the heater now dissipate a power p2 find ratio between p1: p2
Answers
Answered by
10
Final Answer : 1:4
Understanding :
1) Resistance of coil is halved when length of coil is halved as R α l.
2) When two Resistors are parallel,
then
1/R(eq) = 1/ R1 + 1/R2.
3) When Voltage is constant, then P is inversely proportional to R.
Steps:
See Pic.
Understanding :
1) Resistance of coil is halved when length of coil is halved as R α l.
2) When two Resistors are parallel,
then
1/R(eq) = 1/ R1 + 1/R2.
3) When Voltage is constant, then P is inversely proportional to R.
Steps:
See Pic.
Attachments:
MohdSajid1:
good
:)
Answered by
2
☢️PLEASE MARK AS BRAINLIEST☢️
Attachments:
Similar questions