Question

sum of the first 100 natural numbers

Answer 1

Sum of first 100 natural number=1+2+3+4+.......... +100
According to arithmetic progression
a=1
d=1
l=100
n terms=a+(n-1ld=l
1+(n-1)1=100
1+n-1=100
n=100
Sum of n terms =
$\frac{100}{2} \times (a + l)$
$\frac{100}{2} \times (1 + 100)$
$\frac{100}{2} \times 101$
$50 \times 101$
$5050$

Mark it as brainlist