Question

Quadratic Equation:-
1) √3x²-2x+3/5=0
2) (x-3)³+5=x³+7x²-1

Answer 1

in first one directly apply., x=(-b+-(b^2-4ac)^1/2)/2a
in second
x^3-27-9x^2+.......expand=x^3+.....
in next line both x^3 cancelled out and solve the quad eqn from above formula