quadratic equation by factorization method3x²-2√6x+2=0
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x. = 2 root6/3
x = -2 root6/3
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x. = 2 root6/3
x = -2 root6/3
if it helpful please rate it brainliest
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given
3x² -2√6 x+2=0
⇒3x²-√6x -√6x +2=0
⇒√3 *√3 x² - √2*√3 x -√2*√3 x + √2*√2=0
⇒√3x(√3x -√2) -√2(√3x- √2)=0
⇒(√3x-√2) (√3x -√2)=0
therefore
√3x-√2 =0 or √3x-√2=0
√3x= √2
x= √2/√3 equal roots
3x² -2√6 x+2=0
⇒3x²-√6x -√6x +2=0
⇒√3 *√3 x² - √2*√3 x -√2*√3 x + √2*√2=0
⇒√3x(√3x -√2) -√2(√3x- √2)=0
⇒(√3x-√2) (√3x -√2)=0
therefore
√3x-√2 =0 or √3x-√2=0
√3x= √2
x= √2/√3 equal roots
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