Question

quadratic equation using the discriminant x²-5x+4=0​

Answer 1

Answer:

two distinct real root

Step-by-step explanation:

b²-4ac

on comparing

a=1 , b= -5 c= 4

then discriminant

-5²-4×1×4

25-16

=9 >0

so two distinct real roots

Answer 2

Answer:

Step-by-step explanation:

Given

$x^2-5x+4=0$

We need to find the equation has any roots with the help of discriminant.

$D=b^2-4ac\\\\D=(-5)^2-4(1)(4)\\\\D=25-16\\\\D=9>0$

Since the D is greater than zero so the equation has two distinct solutions.