Question

quadratic equation, x² − 2√3x + 3 = 0. Find the value of b² − 4ac.​

Answer 1

SolutioN :-

★ d = b² - 4ac

Here

• a = 1
• b = 2√3
• c = 3

Substitute values in formula :

→ d = ( 2√3 )² - 4 × 1 × 3

→ d = 12 - 12

→ d = 0

Answer 2

Given : Quadratic equation, x² − 2√3x + 3 = 0.

To Find : the value of b² − 4ac.​

Solution:

x² − 2√3x + 3 = 0.

ax² + bx  + c = 0  is the general form of Quadratic equatioon

D = Discriminant = b² - 4ac

comparing  x² − 2√3x + 3 = 0  with ax² + bx  + c = 0

=> a = 1

   b = -2√3

   c   = 3

b² − 4ac  = (-2√3)² - 4(1)(3)

= 12 - 12

= 0

b² − 4ac  = 0  roots are real and equal

b² − 4ac  > 0 roots are real and unequal

b² − 4ac < 0 roots are imaginary

x² − 2√3x + 3 = 0

roots are  √3 , √3

b² − 4ac  = 0

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