Math, asked by mushahid59, 1 year ago

quadratic equations (3t – 1) (3t + 1) = 0

Answers

Answered by SidVK
0
(3t - 1) (3t + 1) = 0

(3t)^2 - (1)^2 = 0

9t^2 - 1 = 0

3t^2 = 1

t^2 = 1/9

t = √(1/9)

t = +1/3.....or.....-1/3....●

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Hope it was helpful.
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