quadratic equations (3t – 1) (3t + 1) = 0
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Answered by
17
Hey !!
( 3T + 1 ) ( 3T - 1 ) = ( 3T)² - (1)²
=> 9T² - 1
=> 9T² = 1
=> T² = 1/9
=> T = √1/9
=> T = 1/3
( 3T + 1 ) ( 3T - 1 ) = ( 3T)² - (1)²
=> 9T² - 1
=> 9T² = 1
=> T² = 1/9
=> T = √1/9
=> T = 1/3
Answered by
1
(3t - 1 ) (3t + 1 ) = 0
(3t)^2 - (1)^2 = 0
9t^2 = 1
t = -1/3 or 1/3
(3t)^2 - (1)^2 = 0
9t^2 = 1
t = -1/3 or 1/3
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