Question

Quadratic Equations:
Find the roots of the following: x2-2x-4=0​

Answer 1

Answer:

x²-2x-4=0

D=b²-4ac

=(-2)²-4(1)(-4)

=4+16

=20

since, D>0

therefore , equation has real and distinct roots

x=( -b+√D)/2a ; (-b-√D)/2a

x=[-(-2)+√20]/2(1) ; [-(-2)-√20]/2(1)

x=(2+2√5)/2 ; (2-2√5)/2

therefore ,

roots =1+√5 ; 1-√5

Answer 2

Step-by-step explanation:

X2-2x-4=0

D=b2-4ac

= (-2)2-4(1)(-4)

=4+16

=20

X=-b+- root D/2a

- (-2)+- root 20/2(1)

2+-root 20/2

2+root20/2 and 2-root 20/2