Question

Quadrilateral abcd is a cyclic quadrilateral lines ab and dc intersect in the point f and lines ad and bc intersect in the. if show that circumcircle of triangle bcf and triangle cd intersect in a point on the line ef​

Answer 1

Answer:

idk

Step-by-step explanation:

Answer 2

Angle in a Semi Circle

Step-by-step explanation:

As we know that, Right Angle is always made in a semi circle.

So, $\angle$FBC = 90° and $\angle$FGC = 90°

Now, on adding the above two angles,

$\angle$FBC + $\angle$FGC = 90° + 90° = 180 °

We can say that,

• FBCG is a Cyclic Quadrilateral.

Similarly,  

• DEGC is also a Cyclic Quadrilateral.

$\angle$FGC + $\angle$EGC = 180° - $\angle$FBE + 180° - $\angle$EDF (FBCG & DEGC are cyclic quadrilateral)

= $\angle$ABE + $\angle$ADF (Linear Pair)

= 180° (Thereby Proves ABCD is a Cyclic Quadrilateral)

Hence we can say FGE is a Straight line.