Question

*Quadrilateral ABCD is a trapezium AB ll CD. Point P & Q are the midpoints of side AD & BC respectively. If AB = 8 cm & PQ = 12 cm then find the length of side CD.*

1️⃣ 8 cm
2️⃣ 12 cm
3️⃣ 20 cm
4️⃣ 16 cm​

Answer 1

Answer:

16

Given AB=12cm , MN=14cm

Since ,segment joining the mid-point of non-parallel sides of trapezium is half the sum of the lengths of its parallel sides.

⇒MN=

2

1

(AB+DC)

14=

2

1

(12+CD)

CD=28−12

CD=16cm

solution

Answer 2

Answer:

1) 8 cm

Step-by-step explanation:

Given , AB || CD

( || means both are parrell or same)

AB = 8 cm

so , CD is also equal to 8 cm

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