quadrilateral angle ABCD AB=5CM BC=6CM ANGLE A=80° ANGLE B=100° ANGLE C=90° ANGLE D=90°
Answers
Answer :
Given : A quadrilateral A B CD, in which, AB=5 cm, BC = 6 cm, CD =6.5 cm, angle B= 105° and angle C = 75°
Steps of construction
(1) Draw a line segment B C of length 6 cm.
(2) At Point B and C, with the help of Compass draw angle of 105° and 75° respectively.Name the rays as C M and B Z respectively.
105°→Draw an angle of 120° and 90° and draw angle bisector between 90° and 120°.
75°→Draw angle bisector of 60° and 90°.
(3) From C, mark an arc at a distance of 6.5 cm on ray CM.You will get point D.
(4) From B, mark an arc at a distance of 5 cm on ray B Z.You will get point A.
(5) Join A and D.
This is required trpzoid A B CD.
here, AB || CD→→<B+<C=180°[If sum of interior
angles on the same side of transversal is supplementary then lines are parallel.]
