Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals . Find the value of x , if JF = 8x + 4 and EG = 24x - 8
Answers
Answered by
175
24x-8=2(8x+4)
24x-8=16x+8
24x-16x=8+8
8x=16
x=16/8
x=2
24x-8=16x+8
24x-16x=8+8
8x=16
x=16/8
x=2
Answered by
66
here JF is half of a diagonal
EG is a diagonal
so,(EG/2)=JF
(or)JF*2=EG
EG=24x-8
JF=8x+4
(24x-8)/2=8x+4
24x-8=2(8x+4). (multiplying)
24x-8=16x+8. (transposing values)
24x-16x=8+8
8x=16
x=16/2
x=8
EG is a diagonal
so,(EG/2)=JF
(or)JF*2=EG
EG=24x-8
JF=8x+4
(24x-8)/2=8x+4
24x-8=2(8x+4). (multiplying)
24x-8=16x+8. (transposing values)
24x-16x=8+8
8x=16
x=16/2
x=8
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