quadrilateral pqrs is a rhombus if its diagonal are having the length 10 cm and 24 cm respectively then find the perimeter of rhombus pqrs
Answers
Step-by-step explanation:
Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse2 = side 2+ side2
Hypotenuse2= 52+ 122
Hypotenuse2 = 25 + 144
Hypotenuse2 = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
Answer
Therefore, the perimeter of the rhombus is 52cm.
Answer:
Diagonals meet at the centre and forms right-angled triangles.
So by using pythagoras theorem
Length of the base = 10/2 = 5cm
Length of the height = 24/2 = 12cm
Hypotenuse² = side ²+ side²
Hypotenuse²= 52+ 122
Hypotenuse² = 25 + 144
Hypotenuse² = 169
On taking square root we get,
Hypotenuse = 13 { 13 X 13=169 => √169=13}
Hence the side of the rhombus is 13cm.
Perimeter of the rhombus = 4×side
= 4 × 13
= 52cm.
Answer
Therefore, the perimeter of the rhombus is 52cm