Question

The diameter of a wire as measured by a screw guage was found to be 0.026cm, 0.028cm, 0.029cm,0.027cm, 0.024cm, 0.027cm. Calculate. 1 - Mean Value of Diameter.. 2 - Mean Absolutely Error.. 3 - Relative and Percentage error.. 4 - Express it with Relative and Percentage error​

Answer 1

Answer:

For the three readings:

mean= 3

1.002+1.004+1.006 cm=1.004 cm

So, absolute error in the third reading:

ΔD 3=1.006−mean

=(1.006−1.004) cm

=0.002 cm