Question

quadrilateral PQRS is rectangle side of rectangle are 8 cm and 15 cm .find the length of diagonal
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Answer 1

`quadrilateral PQRS is rectangle

∴PQ =RS=8 cm

∴QR = PS=15 cm

∴BY PYTOGAROS THEROME

PR² = PS² + SR²

      =15² + 8²

      =225 + 64

      = 289

      =√289

     =17

 ∴PR= QS= 17 cm

Answer 2

Answer:

The length of diagonal is 17 c.m.

Step-by-step explanation:

• PQRS is a given rectangle
• Sides of rectangle PS=8cm and PQ=15cm(Given)  

• Since opposite sides of rectangle are equal

   ⇒PQ=SR=15cm

   ⇒PS=QR=8cm

• In rectangle all the angles are right angles

• Hence length of diagonal = $\sqrt{l^{2}+ b^{2} }$, where l=length of the rectangle and b= breadth of the rectangle

Now in △PQR, using Pythagoras theorem, we have

$PR^{2}$  =  $PQ^{2}$ + $QR^{2}$

⇒ PR = $\sqrt{15^{2}+ 8^{2} }$

⇒ PR =$\sqrt{225+64}$

⇒PR =$\sqrt{ 289}$ = 17 c.m.

​Hence length of diagonal PR=17cm

Similarly length of diagonal QS=17cm.