Question

#Quality answer

★Brainly star

★Brainly moderator, and other best user.


$\sf\small\green{Question:-}$
A mass Is lifted to a height in 10 sec and if the same mass is lifted to the same height in 20 sec the work done in the two cases in the ratio​.

no spam​

Answer 1

Answer :-

Ratio of the work done in the two cases is 1 : 1 . This means same work is done in both cases as it does not depends on time .

Explanation :-

When the mass is lifted to given height, it's work done will be equal to Potential Energy .

W = mgh

For t = 10 sec :-

→ Mass = m

→ Gravitational acceleration = g

→ Height = h

So, work done in this case :-

⇒ W = mgh. ---(1)

For t = 20 sec :-

The same mass is raised to a same height in 20 seconds. So work done, in this case :-

⇒ W' = mgh ---(2)

________________________________

On dividing eq.1 by eq.2, we get :-

⇒ W/W' = mgh/mgh

⇒ W/W' = 1/1

⇒ W : W' = 1 : 1

Answer 2

Given :-

A mass Is lifted to a height in 10 sec and if the same mass is lifted to the same height in 20 sec

To Find :-

Ratio of work done

Solution :-

Let

Height be h

Mass be m

Acceleration due to gravity will be 10 m/s²

Bow

Work done = Energy

In the first case

Work done = m × 10 × h

Work done 1 = 10(mh)

In the second case

Work done = m × 10 × h

Work done 2 = 10(mh)

On dividing both given equation

Work done 1/Work done 2 = 10(mh)/10(mh)

Work done 1/Work done 2 = 10/10

Work done 1/Work done 2 = 1/1

Ratio = 1 : 1