Physics, asked by abhi230204, 1 month ago

☆quality answer needed☆
》A physical quantity Q is given by
q =  \frac{ {a}^{2} {b}^{ \frac{3}{2} }  }{ {c}^{4}  {d}^{ \frac{1}{2} } }
the percentage errors in the A,B,C,D are 1%,2%,4%,2% respectively. find the percentage error in Q.


it is class 11th question
DON'T SPAM. ​

Answers

Answered by Anonymous
20

Answer:

A physical quantity Q is given by :

\footnotesize\implies\sf Q = \dfrac{ {A}^{2} {B}^{ \frac{3}{2} } }{ {C}^{4} {D}^{  \frac{1}{2} } } \\\\

• The percentage errors in the A,B,C,D are 1%,2%,4%,2% respectively.

\footnotesize\implies\sf  \dfrac{\Delta Q}{Q} \times 100 =2 \bigg \{\dfrac{\Delta A}{A} \times 100 \bigg \} + \dfrac{3}{2} \bigg \{\dfrac{\Delta B}{B} \times 100 \bigg \}  + 4\bigg \{\dfrac{\Delta C}{C} \times 100 \bigg \}  +  \dfrac{1}{2}\bigg \{\dfrac{\Delta D }{D} \times 100 \bigg \}  \\\\

\footnotesize\bullet\:\tt\dfrac{\Delta A}{A} \times 100 = 1\%\\\\

\footnotesize\bullet\:\tt\dfrac{\Delta B}{B} \times 100 = 2\%\\\\

\footnotesize\bullet\:\tt\dfrac{\Delta C}{C} \times 100 = 4\%\\\\

\footnotesize\bullet\:\tt\dfrac{\Delta D}{D} \times 100 = 2\%\\\\

\footnotesize\implies\sf  \dfrac{\Delta Q}{Q} \times 100 =2 \bigg \{ 1\%\bigg \} + \dfrac{3}{2} \bigg \{2 \%\bigg \}  + 4\bigg \{4\%\bigg \}  +  \dfrac{1}{2}\bigg \{2\% \bigg \}  \\\\

\footnotesize\implies\sf  \dfrac{\Delta Q}{Q} \times 100 =2\% +  3 \%  + 16\%  +  1\% \\\\

\footnotesize\implies  \gray{\underline{ \boxed{ \orange{\bf  \dfrac{\Delta Q}{Q} \times 100 =22\%}}}}  \\

Answered by rohithkrhoypuc1
8

Answer:

\underline{\purple{\ddot{\Mathsdude}}}

♧Answered by Rohith kumar maths dude :-

I posted your answer on attachment refer it .

I tried it well to answer.

♧♧Thank you.

♧♧Hope it helps u mate .

Attachments:
Similar questions