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class 10th cbse
Answers
Answer:
989 seconds
Step-by-step explanation:
Diameter = 3m
radius = 3/2 = 1.5 m
Volume = 2/3πr^3
= 2/3* 3.14 * 1.5^3
= 7.065 cm^3
= 7065 l
emptying rate = 25/7 l per second
let the time taken to empty half volume = t
= 25/7 * t = 1/2 * volume
t = 1/2 * 7065* 7/25
t = 989 seconds (ANSWER)
hope it helps you
Answer:
990 seconds (or) 16 minutes 30 seconds
Step-by-step explanation:
Given, Diameter of the base of the tank = 3 m.
Then, radius of the tank = (3/2) m.
(i) Volume of hemispherical tank :
= (2/3) πr³
= (2/3) * (22/7) * (3/2)³
= (99/14) m³
= (99000/14) l
(ii) Volume of the tank:
= (1/2) * (99000/14)
= 49500/14 l
Given that rate of water emptied by the pipe is (25/7) l/s.
So, the time taken to empty the half tank =(49500/14) * (7/25)
= 1980/2
= 990 seconds
(or)
= 990/60 minutes
= 16.5 minutes
= 16 minutes 30 seconds
Therefore, Time taken is 990 seconds (or) 16 minutes 30 seconds.
Hope it helps!